(x+5)(x^2+2x-8)=0

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Solution for (x+5)(x^2+2x-8)=0 equation: 


Simplifying
(x + 5)(x2 + 2x + -8) = 0

Reorder the terms:
(5 + x)(x2 + 2x + -8) = 0

Reorder the terms:
(5 + x)(-8 + 2x + x2) = 0

Multiply (5 + x) * (-8 + 2x + x2)
(5(-8 + 2x + x2) + x(-8 + 2x + x2)) = 0
((-8 * 5 + 2x * 5 + x2 * 5) + x(-8 + 2x + x2)) = 0
((-40 + 10x + 5x2) + x(-8 + 2x + x2)) = 0
(-40 + 10x + 5x2 + (-8 * x + 2x * x + x2 * x)) = 0
(-40 + 10x + 5x2 + (-8x + 2x2 + x3)) = 0

Reorder the terms:
(-40 + 10x + -8x + 5x2 + 2x2 + x3) = 0

Combine like terms: 10x + -8x = 2x
(-40 + 2x + 5x2 + 2x2 + x3) = 0

Combine like terms: 5x2 + 2x2 = 7x2
(-40 + 2x + 7x2 + x3) = 0

Solving
-40 + 2x + 7x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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